Re: value of shift???

From: Hironori Ito (hito@students.phsx.ukans.edu)
Date: Wed Dec 26 2001 - 01:10:25 EST

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    	Hello.  I need to take a one centence from the previous
    mail.  That is "No shift=No data".  After reading the old papers and
    talking to Challis, the cosmic rays emulation experiment by
    balloon during 50s and 60s did not require any shifts at all.  They
    just built the detectors and sent them to somewhere in Colorado, where
    people mounted the detectors in the balloon and let it go.  (I guess they
    estimated (or hoped) the landing location.)  After landing (somewhere in
    Texas) they (not physicists) collected the detectors and sent them back to
    the physicists for analysis.  Therefore, it was "Data w/o Shift".
    
    	Ok, since I can hear the complaints from the senior people who do
    a lot of administrative work, I will add one more factor by age.  Assuming
    the olddest and youngest ages in our group are 75 and 25, here is the
    formula, (age-25)*(beam shift weeks/2)/25.  Therefore,  if you are age 75
    and 20 weeks of Au runs, you get (75-25)*(20/2)/25=20 shifs, which is
    reasonable.  (Ok, I am just having a fun!!!)
    
    	Hiro
    
    Note:  While researching the old paper for high energy nuclear
    collisions, I found the papers by Enrico Fermi in 1950 and 1951.  There,
    he layed out many of the basic ideas for the current RHIC physics without
    quark and gluon Mambo-Jumbo. (He seems to be the first one ahead of
    Landau.)   (Of cause, he got the wrong conclusion, but that is not really
    important.)  After 50+ years, we are still doing what he proposed.  I
    would say he was very sharp. Wow!!!
    



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