¥Based on the number of
charged particles detected we can estimate our efficiency for d + Au:
¥P
side: P(NP = 0) = 0.30
¥N
side: P(NN = 0) = 0.12
¥Vertex
efficiency = P(NP >
0) x P(NN > 0) = 0.62
¥Collision
time efficiency = 1 - P(NP = 0) x P(NN = 0) = 0.96
¥Note: the numbers quoted
here are the number of primary particles.
The number of secondaries is a factor of 2 - 3 larger than the number of
primaries.
¥Saturation
certainly will not be a problem for d + Au.