Re: [Brahms-l] lambda/p ratio vs rapidity

From: Peter Christiansen <peter.christiansen_at_hep.lu.se>
Date: Thu, 13 Aug 2009 10:23:03 +0200
Dear Michael,

I have tried to play with these things from another angle once
(following chemical ideas of BRAHMS, you, and others) that might be
useful. If you would have chemical equilibration at each rapidity you
would expect:
K^+-K^- ~ Lambda - Lambda-bar

If I look at NA49 data this does not seem so bad an estimate, see
attached plot (there is one of the data sets where the centralities are
not the same for Ks and Lambdas as I remember).

It might not help you to get p/Lambda (or the pT dependence - I think
Flemming has done some work on this), but it might give some cross
check:-)

Cheers,
   Peter

On Wed, 2009-08-12 at 17:15 -0500, Michael Murray wrote:
> Dear Casper,
>                   BRAHMS has found that the strange chemical  
> potential m_s = 0.28 +- 0.04 * m_q
> Since lambda is like a proton that has an up quark changed to a  
> strange quark then lambda/p is proportional to exp (mu_s - mu_q) =  
> exp (0.72 mu_q)  or (pbar/p)**0.12
> 
> Given the change of pbar/p from 0.75 to 0.23 from y=0 to y=3.1 I find  
> that the lambda/proton ratio should decrease by a factor of 0.86+-0.02
> 
> The antilambda/antiproton ratio should INCREASE by this factor.
> 
> This seems like a reasonable estimate for the overall change in the  
> ratio. I will work on the Pt dependence next.
> Michael
> 
> 
> 
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-- 
Peter Christiansen
Email: peter.christiansen_at_hep.lu.se
Phone: (+46) 046-2227709

Address:
Lund University
Department of Physics
Div. of Experimental High-Energy Physics
Box 118
SE-221 00 Lund
Sweden


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na49_net_lambda_vs_net_k.gif
Received on Thu Aug 13 2009 - 06:46:55 EDT

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